3.2507 \(\int \frac {x}{(a+b x^n)^{3/2}} \, dx\)

Optimal. Leaf size=48 \[ \frac {x^2 \, _2F_1\left (1,\frac {2}{n}-\frac {1}{2};\frac {n+2}{n};-\frac {b x^n}{a}\right )}{2 a \sqrt {a+b x^n}} \]

[Out]

1/2*x^2*hypergeom([1, -1/2+2/n],[(2+n)/n],-b*x^n/a)/a/(a+b*x^n)^(1/2)

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Rubi [A]  time = 0.02, antiderivative size = 60, normalized size of antiderivative = 1.25, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {365, 364} \[ \frac {x^2 \sqrt {\frac {b x^n}{a}+1} \, _2F_1\left (\frac {3}{2},\frac {2}{n};\frac {n+2}{n};-\frac {b x^n}{a}\right )}{2 a \sqrt {a+b x^n}} \]

Antiderivative was successfully verified.

[In]

Int[x/(a + b*x^n)^(3/2),x]

[Out]

(x^2*Sqrt[1 + (b*x^n)/a]*Hypergeometric2F1[3/2, 2/n, (2 + n)/n, -((b*x^n)/a)])/(2*a*Sqrt[a + b*x^n])

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rule 365

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[(a^IntPart[p]*(a + b*x^n)^FracPart[p])
/(1 + (b*x^n)/a)^FracPart[p], Int[(c*x)^m*(1 + (b*x^n)/a)^p, x], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[
p, 0] &&  !(ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {x}{\left (a+b x^n\right )^{3/2}} \, dx &=\frac {\sqrt {1+\frac {b x^n}{a}} \int \frac {x}{\left (1+\frac {b x^n}{a}\right )^{3/2}} \, dx}{a \sqrt {a+b x^n}}\\ &=\frac {x^2 \sqrt {1+\frac {b x^n}{a}} \, _2F_1\left (\frac {3}{2},\frac {2}{n};\frac {2+n}{n};-\frac {b x^n}{a}\right )}{2 a \sqrt {a+b x^n}}\\ \end {align*}

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Mathematica [A]  time = 0.02, size = 60, normalized size = 1.25 \[ \frac {x^2 \sqrt {\frac {b x^n}{a}+1} \, _2F_1\left (\frac {3}{2},\frac {2}{n};1+\frac {2}{n};-\frac {b x^n}{a}\right )}{2 a \sqrt {a+b x^n}} \]

Antiderivative was successfully verified.

[In]

Integrate[x/(a + b*x^n)^(3/2),x]

[Out]

(x^2*Sqrt[1 + (b*x^n)/a]*Hypergeometric2F1[3/2, 2/n, 1 + 2/n, -((b*x^n)/a)])/(2*a*Sqrt[a + b*x^n])

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*x^n)^(3/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x}{{\left (b x^{n} + a\right )}^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*x^n)^(3/2),x, algorithm="giac")

[Out]

integrate(x/(b*x^n + a)^(3/2), x)

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maple [F]  time = 0.20, size = 0, normalized size = 0.00 \[ \int \frac {x}{\left (b \,x^{n}+a \right )^{\frac {3}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(b*x^n+a)^(3/2),x)

[Out]

int(x/(b*x^n+a)^(3/2),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x}{{\left (b x^{n} + a\right )}^{\frac {3}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*x^n)^(3/2),x, algorithm="maxima")

[Out]

integrate(x/(b*x^n + a)^(3/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {x}{{\left (a+b\,x^n\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(a + b*x^n)^(3/2),x)

[Out]

int(x/(a + b*x^n)^(3/2), x)

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sympy [C]  time = 1.41, size = 41, normalized size = 0.85 \[ \frac {x^{2} \Gamma \left (\frac {2}{n}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{2}, \frac {2}{n} \\ 1 + \frac {2}{n} \end {matrix}\middle | {\frac {b x^{n} e^{i \pi }}{a}} \right )}}{a^{\frac {3}{2}} n \Gamma \left (1 + \frac {2}{n}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(a+b*x**n)**(3/2),x)

[Out]

x**2*gamma(2/n)*hyper((3/2, 2/n), (1 + 2/n,), b*x**n*exp_polar(I*pi)/a)/(a**(3/2)*n*gamma(1 + 2/n))

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